a. Calculate the total resistance of the circuit.

b. Calculate the current in the circuit.

c. Calculate the power of each bulb.

d. Calculate the power supplied by the battery.

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## Answers

## BettieZumbrunnen

a). Since the bulbs are in series, their total resistance is the sum of their individual resistances. The total resistance in the series circuit is 6 ohms.

b). The current in the circuit is (voltage between the ends) / (total resistance) .

Current = 12 V / 6 ohms = 2 Amperes.

c). The power dissipated by any component can be expressed in different ways,

and if we're smart, we pick the formula that makes the problem easy for us.

-- Power = (voltage) x (current)

-- Power = (current)² x (resistance)

-- Power = (voltage)² / (resistance)

For this one, I think the middle formula is easiest.

Power = (current)² x (resistance) = (2 A)² x (3 ohms) = 12 watts for each bulb

d). Each bulb dissipates 12 watts,so for both bulbs, the battery has to supply 24 watts.

Check this solution with the first formula for power, above:

-- Power = (voltage) x (current)

Battery power = (battery voltage) x (current) = (12 V) x (2 A) = 24 watts Check. yay!