A solutin contains 100.0 g water, 10.0 g NaCl, and 15.0 g Methanol. What is the Mass Percent of methanol in the solution? The answer is 12.0% but I do not understand why. I know that Mass % = Mass solute/(mass solute + mass solvent) and then the whole thing X 100%. Please help me to see what I am missing in how to correctly solve for these kinds of equations.
3 years ago Comment
Mass percent of methanol :
% mass = mass methanol / mass total
% mass = 15.0 / 100.0 + 10.0 + 15.0
% mass = 15.0 / 125.0
% mass ( methanol ) = 0,12 x 100 = 12%
hope this helps!