A. 10.4

B. 16

C. 12.2

D. 11.8

An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip?

A. 165 units

B. 170 units

C. 97 units

D. 169 units

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## Answers

## ElizbethLiddle208

1. The distance formula given two points is,

d = sqrt ((x2 - x1)² + (y2 - y1)²)

Substituting the given values,

d = sqrt ((12 - 0)² + (3 - 5)²) = 12.17 or aproximately 12.2

2. Calculate the distance between points T and U and from U to V

( T to U) d = sqrt ((20 - 80)² + (60 - 20)²) = 72.11

(U to V) d = sqrt ((110 - 20)² + (85 - 60)²) = 93.41

Adding this distances gives an answer of approximately equal to 165.52. The answer is letter A.