Mathematics

how to solve 2^(log(2)3+ log(2)5


Answers

yassautumn

4 years ago Comment

[latex]2^{\log_23+ \log_25 }=\\ 2^{\log_215}=\\ 15[/latex]

lyssie11234

4 years ago Comment

[latex]2^{log_23+log_25}=2^{log_2(3\cdot5)}=2^{log_215}=15\\\\---------------------------\\\\for\ a,b,c\in\mathbb{R^+}\\\\log_ab+log_ac=log_a(b\cdot c)\\\\a^{log_ab}=b[/latex]