Mathematics

# I need to find the zeros of the function: f(x)=2x^2-5x-3

$2x^2-5x-3=0\\ 2x^2-2x-3x-3=0\\ 2x(x+1)-3(x+1)=0\\ (2x-3)(x+1)=0\\ x=\frac{3}{2} \vee x=-1$