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## Answers

## TamaraTewksbury170

First, we must expand and simplify :

[latex]x + y+z = 9[/latex]

[latex](x + y+z)^{2} = (9)^{2}[/latex]

[latex]x^{2} + y^{2}+z^{2} + 2(xy + yz+zx) = 81[/latex]

And Than, Enter the value :

[latex]x^{2} + y^{2}+z^{2} + 2(26) = 81[/latex]

[latex]x^{2} + y^{2}+z^{2} + 52 = 81[/latex]

[latex]x^{2} + y^{2}+z^{2} = 81- 52[/latex]

[latex]\boxed{x^{2} + y^{2}+z^{2} = 29}[/latex]

## Malafronte41

we know,

(x + y + z)² = x² + y² + z² + 2(xy + yz + xz)

9² = x² + y² + z² + 2 X 26

81 = x² + y² + z² + 52

81 - 52 = x² + y² + z²

therefore, x² + y² + z² = 29