Mathematics

Solving by factoring 10p²+6=476


Answers

yassautumn

4 years ago Comment

[latex]10p^2+6=476\\ 10p^2-470=0\\ 10(p^2-47)=0\\ p=-\sqrt{47} \vee p=\sqrt{47}[/latex]

Gracie216

4 years ago Comment

[latex] 10p^2+6=476\\ \\ 10p^2+6-476 =0 \\ \\10p^2-470 =0\ \ /:10 \\ \\ p^2-47 =0 \\ \\(p-\sqrt{47})(p+\sqrt{47})=0 \\ \\p-\sqrt{47}=0 \ \ or \ \ p+\sqrt{47} =0 \\ \\p=\sqrt{47} \ \ or \ \ p=-\sqrt{47} [/latex]