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- jackiepc1128 15.00

## Answers

## yassautumn

[latex]10p^2+6=476\\ 10p^2-470=0\\ 10(p^2-47)=0\\ p=-\sqrt{47} \vee p=\sqrt{47}[/latex]

## Gracie216

[latex] 10p^2+6=476\\ \\ 10p^2+6-476 =0 \\ \\10p^2-470 =0\ \ /:10 \\ \\ p^2-47 =0 \\ \\(p-\sqrt{47})(p+\sqrt{47})=0 \\ \\p-\sqrt{47}=0 \ \ or \ \ p+\sqrt{47} =0 \\ \\p=\sqrt{47} \ \ or \ \ p=-\sqrt{47} [/latex]