The figure is made up of two identical squares and has a perimeter of 42 inches. What is the area of one square?
first solve for the perimeter of the rectangle2w + 2l = 42since the length of the rectangle is twice as long as the length and width of the square2w = lsolve using substitution2w + 2(2w) = 42
2w + 4w = 42
6w = 42
w = 7are is length x width. a square has the same length and width7 x 7 = 49the area of one square is 49