(b) Determine the length of time the bullet is accelerated.

(c) Find the speed at which the bullet leaves the barrel.

(d) What is the length of the barrel?

- During exercise the body cools itself by sweating. sweating in response to an elevated body temperat... 1 year ago
- Surveys show that people who use calorie information to decide which foods to eat consume on average... 1 year ago
- A(n) _____ competitor provides a product or service that a consumer might buy instead of yours even... 1 year ago
- Tell us about a mistake you've made in your past and what you learned from that mistake. fire fighte... 1 year ago
- You work in an important and visible position in government. your decision is to choose between two... 1 year ago

- What does Mark Twain satirize in this excerpt from "The £1,000,000 Bank-Note"? It was a lovely di... 232 Views 1 year ago
- Which statement best describes the role of a credit agency? A.It tracks the use of credit for lend... 218 Views 1 year ago
- What unique accomplishment did ruben Dario achieve at the age of 18? A. he graduated from university... 210 Views 1 year ago
- It is a good idea to learn about a food supplier's warehouse practices. The best way to gather the i... 189 Views 2 years ago
- “doctor, if you can find a new treatment that will cure me, i will buy the hospital a new cancer win... 148 Views 1 year ago

- kbug1449 50.00

## Answers

## ElizbethLiddle208

I'm assuming you're in calculus based physics. I apologize if otherwise. Let's come up with equations for distance and acceleration as functions of time. From the definition of acceleration we know thata=dvdtTaking the derivative of v with respect to t yieldsa=dvdt=(−5.15∗107)∗2∗t+(2.30∗105) From the definition of distance, we know that v=dxdt→dx=vdtIntegrating velocity yieldsx=(−5.15∗107)∗(t33)+(2.30∗105)∗(t22)+x0 where x0 is the starting position. If acceleration is zero when the bullet leaves the barrel, we can use our equation for acceleration to determine the time the bullet is in the barrel. This is seen as0=(−5.15∗107)∗2∗t+(2.30∗105)→t=−(2.30∗105)(−5.15∗107) Knowing time, we can solve for the velocity as the bullet leaves the barrel by plugging time back into our given equation for velocity. The length of the barrel can be solved by plugging time back into our equation for distance and setting x0=0.