Physics

What is the magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge? 


Answers

jferrufino13

4 years ago Comment

In an electric field force,F= q₁q₂/4πε₀ r²  (coulomb's law)  as we know,F=qE  E=F/q
E=q/4πε₀ r²
here,r= 0.0075 m
       q= 0.0035 C
      1/4πε₀  = 9×10⁹
        E=  9×10⁹× 0.0035/(0.0075)²
          =5.6 ×10¹¹ N/C