Mathematics

what is the solution to the equation [latex]\frac{-4(x-8)}{5}[/latex] = 2(3x+1)+[latex] \frac{2}{5} [/latex]
please explain the steps


Answers

yassautumn

4 years ago Comment

[latex]\frac{-4(x-8)}{5}=2(3x+1)+\frac{2}{5}\\ -4(x-8)=10(3x+1)+2\\ -4x+32=30x+10+2\\ 34x=20\\ x=\frac{20}{34}=\frac{10}{17}[/latex]

Gracie216

4 years ago Comment

[latex]\frac{-4(x-8)}{5} = 2(3x+1)+ \frac{2}{5}\ \ / \cdot 5\\ \\5\cdot \frac{-4(x-8)}{5} = 5\cdot 2(3x+1)+5 \frac{2}{5} \\ \\ -4(x-8) = 10(3x+1)+ 2 \\ \\-4x+32=30x+10+2[/latex]

[latex]-4x-30x=10+2 -32\\ \\-34x =-20 \ \ /:(-34)\\ \\x=\frac{20}{34}\\ \\x=\frac{10}{17}[/latex]