Physics

# You're driving down the highway late one night at 18m/s when a deer steps onto the road 39m in front of you. Your reaction time before stepping on the brakes is 0.50s , and the maximum deceleration of your car is 12m/s2 . How much distance is between you and the deer when you come to a stop? =17m What is the maximum speed you could have and still not hit the deer? = ?

#### iza90290

2 years ago

a) Mind you before your reaction time, you had be going at a uniform speed 18m/s, so for the reaction time of 0.5 seconds, you had covered a distance of:

18m/s*0.5s = 9 m

For the second part which involved deceleration, using:

v = u - at,  Noting that there is deceleration.

u = 18m/s, v = final velocity = 0, a = -12m/s².

Let us solve for the time.

v = u + at

0 = 18 - 12*t

12t = 18

t = 18/12 = 1.5 seconds.

Let us compute for the distance covered during the 1.5s

s = ut + 1/2at²,       a = -12 m/s²

s = 18*1.5 -0.5*12*1.5² = 13.5m

So the total distance covered = Distance covered from reaction time + Distance covered from deceleration

= 9m + 13.5m = 22.5m

So you have covered 22.5m out of the initial 39m.

Distance between you and the dear:   39 - 22.5  = 6.5m

So you have 6.5m between you and the deer. So you did not hit the deer.

b) Maximum speed you still have:

Well through trial and error, if you maintain the same values of deceleration, reaction time, distance between the car and the deer, you could have a speed of 25 m/s and still not hit the deer. Once it is higher than that by a significant amount you would hit the deer.